See the electrical circuit shown in this figu | vedclass

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(D) Applying Kirchhoff's voltage law to the loop $ABFE$ in the clockwise direction:Starting from point $A$ and moving towards $B$,the potential drop a

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$\varepsilon _1 - (i_1 + i_2)R - i_1 r_1 = 0$

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(D) Applying Kirchhoff's voltage law to the loop $ABFE$ in the clockwise direction:Starting from point $A$ and moving towards $B$,the potential drop across resistor $R$ is $-(i_1 + i_2)R$.Moving from $F$ to $E$ through the branch containing $\varepsilon_1$ and $r_1$,we encounter the negative terminal of the battery first,so we add $\varepsilon_1$,and then we pass through the resistor $r_1$ in the direction of current $i_1$,resulting in a potential drop of $-i_1 r_1$.Equating the sum of potential changes to zero,we get:$-(i_1 + i_2)R + \varepsilon_1 - i_1 r_1 = 0$Rearranging the terms,we obtain:$\varepsilon_1 - (i_1 + i_2)R - i_1 r_1 = 0$

See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it?

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